These NEET physics practice questions cover common calculations in electricity, waves, mechanics and measurement. Try each one before reading the solution. They are practice examples, not predictions or a verified list of questions from previous NEET papers.
Solutions checked on 10 October 2026. Each example includes the values, units and steps needed to work out the answer.
Use the NEET exam pattern guide when planning a timed paper. The exam’s total duration is not a separate time allowance for Physics.
1. Current drawn by an ideal transformer
A lamp rated 12 V, 48 W runs from an ideal step-down transformer connected to a 240 V supply. What current does the primary winding draw?
Answer: 0.20 A. An ideal transformer has no power loss, so input power equals output power. Primary current = power ÷ primary voltage = 48 ÷ 240 = 0.20 A.
The secondary current is different: 48 ÷ 12 = 4 A. Check which winding the question asks about.
2. Magnetic field of an electromagnetic wave
An electromagnetic wave in free space has a peak electric field of 60 V/m. Find its peak magnetic field. Use c = 3 × 108 m/s.
Answer: 2 × 10−7 T. The relation is E0 = cB0. Therefore B0 = 60 ÷ (3 × 108) = 2 × 10−7 T.
Use peak values on both sides. If the electric field is given as an RMS value, first convert it to the peak value when required.
3. Stretching a wire
A wire has resistance R. It is stretched to three times its original length, with unchanged volume and resistivity. Find its new resistance.
Answer: 9R. Resistance = resistivity × length ÷ area. With volume unchanged, tripling the length reduces the area to one-third. New resistance = ρ(3L) ÷ (A/3) = 9ρL/A = 9R.
The unchanged-volume condition matters. You cannot use this result if the problem changes the material or volume.
4. Acceleration after starting from rest
A train starts from rest and reaches 36 km/h in five minutes with uniform acceleration. Find its acceleration in m/s².
Answer: approximately 0.0333 m/s². First convert 36 km/h to 10 m/s and five minutes to 300 seconds. Acceleration = (final velocity − initial velocity) ÷ time = (10 − 0) ÷ 300.
Converting the units before substituting avoids the most common error in this calculation.
5. Magnetic flux through a loop
A square loop has a side of 0.50 m. A uniform magnetic field of 0.40 T is perpendicular to its plane. Find the magnetic flux.
Answer: 0.10 Wb. Area = 0.50 × 0.50 = 0.25 m². Magnetic flux = BA cos θ, where θ is the angle between the field and the normal to the loop. Here θ = 0°, so flux = 0.40 × 0.25 = 0.10 Wb.
The angle is measured from the normal, not from the plane of the loop.
6. Pitch of a screw gauge
A screw gauge has 50 circular-scale divisions and a least count of 0.01 mm. Find its pitch.
Answer: 0.50 mm. Least count = pitch ÷ number of divisions. Therefore pitch = 0.01 × 50 = 0.50 mm.
For an actual reading, check the instrument’s zero error separately.
7. Image formed by a convex lens
An object 2 cm high is placed 30 cm from a thin convex lens with a focal length of 10 cm. Find the image distance and height using the Cartesian sign convention.
Answer: 15 cm on the other side; image height −1 cm. Here u = −30 cm and f = +10 cm. From 1/f = 1/v − 1/u, we get 1/10 = 1/v + 1/30. Therefore 1/v = 1/15 and v = +15 cm.
Magnification = v/u = 15/(−30) = −0.5. Image height = −0.5 × 2 = −1 cm. The image is real, inverted and half the object’s height.
8. Force during uniform circular motion
A 0.20 kg particle moves at 3 m/s in a circle of radius 0.50 m on a smooth horizontal surface. A horizontal string provides the centripetal force. Find its tension.
Answer: 3.6 N. The required inward force is mv²/r = 0.20 × 9 ÷ 0.50 = 3.6 N. In this setup, the string tension supplies that force.
Do not add a separate “centripetal force” to the tension. Centripetal force names the net force directed towards the centre.
How to use these questions
After each attempt, note whether your error came from the concept, formula, units or arithmetic. Rework that question without looking at the solution. Then practise different values so you learn the method rather than memorise the answer.
For a full mock test, follow the current syllabus and paper instructions. Our NEET pattern comparison explains why an old paper’s optional sections should not be carried into a different exam format.
Use the NEET UG guide for the application and admission steps beyond exam practice.
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